mmarco/kenzo
1
0
Fork 0
Code Issues Pull Requests Releases Wiki Activity

Fixed LaTeX compilation errors.

Browse Source
This commit is contained in:
Gerd Heber 2018-02-11 18:53:54 -06:00
parent 3f018492c9
commit 30a4963bcc
1 changed files with 5 additions and 4 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

7
examples/pcl/Packages_in_Common_Lisp.org
View File

@ -1,6 +1,7 @@
#+TITLE: Packages in Common Lisp, a tutorial #+TITLE: Packages in Common Lisp, a tutorial
#+AUTHOR: Francis Sergeraert #+AUTHOR: Francis Sergeraert
#+DATE: January 2014 #+DATE: January 2014
#+OPTIONS: toc:nil
* Introduction. * Introduction.
@ -1843,7 +1844,7 @@
The inherited symbols of a package $p$, denoted by $InhS(p)$, are defined as: The inherited symbols of a package $p$, denoted by $InhS(p)$, are defined as:
$$ $$
InhS(p) := \Big\{ \bigcup_{q\in U(P)}(ExS(q) − ShdS(q,p)) \Big\} − PrS(P) InhS(p) := \Big\{ \bigcup_{q\in U(P)}(ExS(q) - ShdS(q,p)) \Big\} - PrS(P)
$$ $$
A symbol is inherited in a package $p$ if it is external in a /used/ package A symbol is inherited in a package $p$ if it is external in a /used/ package
@ -1851,7 +1852,7 @@
union in the preceding formula is not necessarily disjoint: a symbol can be union in the preceding formula is not necessarily disjoint: a symbol can be
external in several packages simultaneously, and without causing a name external in several packages simultaneously, and without causing a name
conflict. A symbol could be simultaneously present in $p$ and external in a conflict. A symbol could be simultaneously present in $p$ and external in a
package $q$ used by $p$. That is why the the last term, $−PrS(P)$, is package $q$ used by $p$. That is why the the last term, $-PrS(P)$, is
necessary to define unambiguously what an inherited symbol is. necessary to define unambiguously what an inherited symbol is.
Finally the accessible symbols $AccS(p) := PrS(p) \cup InhS(p)$ are the Finally the accessible symbols $AccS(p) := PrS(p) \cup InhS(p)$ are the
@ -2142,7 +2143,7 @@
the new set of accessible symbols via $p$ is: the new set of accessible symbols via $p$ is:
$$ $$
\mathrm{new-}AccS(p) = \mathrm{old-}AccS(p) \cup (ExS(q) − ShdS(q, p)) \mathrm{new-}AccS(p) = \mathrm{old-}AccS(p) \cup (ExS(q) - ShdS(q, p))
$$ $$
** (unuse-package $q$ $p$) ** (unuse-package $q$ $p$)